2\overx-2-3\overx-5=-15\overx^2-7x+10

\frac{2}{x-2}-\frac{3}{x-5}=-\frac{15}{x^2-7x+10} Dziedzina: \Delta=b^2-4ac \Delta=(-7)^2-4\cdot 1\cdot 10 \Delta=49-40=9 \sqrt \Delta =3 x_1=\frac{7-3}{2}=2 x_2=\frac{7+3}{2}=5 x\in R-{2,5} \frac{2}{x-2}-\frac{3}{x-5}=-\frac{15}{x^2-7x+10} \frac{2}{x-2}-\frac{3}{x-5}=-\frac{15}{(x-2)(x-5)} \frac{2(x-5)}{(x-2)(x-5)}-\frac{3(x-2)}{(x-5)(x-2)}=-\frac{15}{x^2-7x+10} \frac{2(x-5)-3(x-2)}{(x-2)(x-5)}=-\frac{15}{x^2-7x+10} 2(x-5)-3(x-2)=-15 2x-10-3x+6=-15 -x=-15+4 -x=-11 x=11