Rozwiąż metodą podstawiania a). 3x - 2y = 4 x + 5y = 7 b). 4x + 2y = 8 5x + 3y = 9 c). x-2/3 + 2y = x+y/2 2(x-y) = 5-3(x-2)

a) 3x - 2y = 4 x + 5y = 7 x=7-5y 3(7-5y)-2y=4 21-15y-2y=4 -17y=-17 y=1 x+5*1=7 x+5=7 x=7-5 x=2

b) 4x + 2y = 8 5x + 3y = 9 x=2-0,5y 5(2-0,5y)=9 10-2,5y + 3y=9 0,5y=-1 y=-2 5x+3(-2)=4 5x-6=4 5x=15 x=3

4x+2y=8 5x+3y=9 2y=8-4x /:2 5x+3y=9 y=4-2x 5x+3(4-2x)=9 y=4-2x 5x+12-6x=9 y=4-2x -x=-3/*(-1) y=4-2x x=3 y=4-2*3 x=3 y=-2 x=3 wydaje mi sie,że dobrze ;)